Calculations › Shear Design
Shear Design
EN 1992-1-1
Designs shear links for a rectangular beam or slab section to EN 1992-1-1 §6.2 using the variable strut inclination method (cot θ = 2.5).
Example inputs
Web width bw300 mm
Effective depth d450 mm
Concrete gradeC25/30
Long. reinforcement ratio ρl0.012 —
Design shear VEd150 kN
Link diameter8 mm
Link spacing200 mm
Link legs2 —
National AnnexUK
Results
Shear Design
EN 1992-1-1 §6.2 · C25/30 · bw=300mm · d=450mm
Results
✓ VRD MAX PASS
util 0.42150.00EN 1992-1-1 §6.2.3
| Lever arm z = 0.9d | 405 | mm | |
| ν₁ (strength reduction) | 0.6 | — | EN 1992-1-1 §6.2.3 |
| VRd,max (cot θ = 2.5) = bw·z·ν₁·fcd / (cot θ + tan θ) | 356.2 | kN | EN 1992-1-1 §6.2.3 |
| VEd | 150 | kN |
✓ VRD S PASS
util 0.68150.00EN 1992-1-1 §6.2.3
| Asw (per link set) = n·π·ø²/4 | 100.53 | mm² | |
| fywd = fyk / γs | 434.78 | N/mm² | |
| VRd,s = (Asw/s) · z · fywd · cot θ | 221.28 | kN | EN 1992-1-1 §6.2.3 |
| VEd | 150 | kN |
✓ MIN REINFORCEMENT PASS
util 2.000.00EN 1992-1-1 §9.2.2
| ρw,min = 0.08·√fck / fyk | 0.001 | — | EN 1992-1-1 §9.2.2 |
| ρw provided = Asw / (bw · s) | 0.002 | — |
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